viernes, 18 de diciembre de 2020

                                                           PROPUESTAS


( P / 100 ) * N = 1 * n + 2 * ( n – 1 ) + 3 * ( n – 2 ) +..... + ( n – 2 ) * 3 + ( n – 1 ) * 2 + n * 1

i = n

= ∑ [ i . [ n – ( i – 1 ) ]

i = 1

= 2n+4(n-1)+6(n-2)+...n/2(n/2+1)

1 * n ! + 2 * ( n – 1 ) ! + 3 * ( n – 2 ) ! +..... + ( n – 2 ) * 3 ! + ( n – 1 ) * 2 ! + n * 1 !

i = n

= ∑ i . { [ n – ( i – 1 ) ] ! }

i = 1

i = n

= ∑ i ! . { [ n – ( i – 1 ) ] }

i = 1

------------------------------------------------------------------------------------------------------------- 

i = n !

[ i . [ n – ( i – 1 ) ]

i = 1

---------------------------------------------------------------------------------------------------------------∫xdx = d(∫xdx)/dx → x2/2+c =d(x2/2+c)/dx = x → x2-2x+2c=0 →

x=1+-sqr(1-2c) → recta vertical


dx = d(∫dx)/dx → x+c =d(x+c)/dx = 1 → x=1-c → recta vertical

1 * n 2 + 2 * ( n – 1 ) 2 + 3 * ( n – 2 ) 2 +..... + ( n – 2 ) * 3 2 + ( n – 1 ) * 2 2 + n * 1 2

i = n

= ∑ { i 2 . [ n – ( i – 1 ) ] }

i = 1

i = n

= ∑ { i . [ n – ( i – 1 ) ] } 2

i = 1

1 * n 2 + 2 * ( n – 1 ) 2 + 3 * ( n – 2 ) 2 +..... + ( n – 2 ) * 3 2 + ( n – 1 ) * 2 2 + n * 1 2

i = n

= ∑ i . [ n – ( i – 1 ) ] 2

i = 1

i = n

= ∑ i . [ n 2 + ( i – 1 ) 2 – 2 . n . ( i – 1 ) ]

i = 1

i = n

= ∑ i . ( n 2 + i 2 – 2 . i + 1 – 2 . n . i + 2 . n )

i = 1

i = n

= ∑ ( i . n 2 + i 3 – 2 . i 2 + i – 2 . n . i 2 + 2 . n . i )

i = 1

i = n

= ∑[i3+i2(-2-2n)+i.(1+2n)]

i = 1

---------------------------------------------------------------------------------------------------------------

i = n

= ∑ { i 2 . [ n – ( i – 1 ) ] }

i = 1

i = n

= ∑ [ i 2 . n – i 2 . ( i – 1 ) ] ]

i = 1

i = n

= ∑ ( i 2 . n – i 3 + i 2 )

i = 1

i = n

= ∑ ( i 2 . ( n + 1 ) – i 3 )

i = 1


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